Resultat for Robin Bjørnetun Jacobsen vs. Andreas Finnøy
Opgave Robin Bjørnetun Jacobsen Andreas Finnøy
(2/3) + (3/8) = 25/2425/2425/24
(5/3) / (1/6) = 10/110/110/1
(3/3) * (5/4) = 5/45/45/4
(3/8) - (1/8) = 1/41/41/4
(7/6) + (5/5) = 13/613/613/6
(1/4) + (7/5) - (6/5) = 9/209/209/20
(4/5) - (1/4) = 11/2011/2011/20
(3/4) - (3/5) = 3/203/203/20
(6/6) + (5/7) = 12/712/712/7
(2/5) + (7/2) = 39/1039/1039/10
Poeng: 10 10
Tidsbruk: 0:39.953 0:31.031
Dato: 29.10.06 10:57:51 29.10.06 17:35:36

Andreas Finnøy vinner kampen.

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